feat: land superpaper v1 notes scaffold

Add the ledger schema, class router, lint codes, ingest/build
pipeline, and three work-tree examples: align derivation,
superfig delegation, and supertensor delegation.

examples/tensor-delegate/notes/figures/F2/F2-mechanism.md

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+$S^{(i)}=Q^{(i)}K^{(i)\top}$。收缩维 $d_h$ 在两个操作数上同一边长；$K^\top$ 换面。

examples/tensor-delegate/notes/figures/F2/F2.request.md

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+# Figure request F2
+toolkit: supertensor
+language: cjk
+claim: 每头打分沿 d_h 收缩；K^T 必须物理换面。
+grammar: tensor-face
+work_rel_dir: figures/F2
+
+## Roles
+- {role: q, color: stTeal}
+- {role: k, color: stOrange}
+- {role: s, color: stCoral}
+
+## Geometry
+- {axis: T, cells: 6}
+- {axis: dh, cells: 3}
+
+## Flow
+stage: {name: SA, text: "每头打分：沿 $d_h$ 收缩"}
+row: {name: rowA, height: T}
+in_row:
+  - {macro: ststack, name: Q,  role: q, coord: "", rows: T,  cols: dh, sheets: 3, bracket: true}
+  - {macro: stglyph, name: mA, coord: "", glyph: "$\\times$"}
+  - {macro: ststack, name: KT, role: k, coord: "", rows: dh, cols: T,  sheets: 3, bracket: true}
+  - {macro: stglyph, name: eA, coord: "", glyph: "$=$"}
+  - {macro: ststack, name: S,  role: s, coord: "", rows: T,  cols: T,  sheets: 3}

examples/tensor-delegate/notes/figures/F2/F2.tex

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+\documentclass[border=10pt]{standalone}
+\usepackage[cjk]{supertensor}
+
+\stsetrole{q}{stTeal}
+\stsetrole{k}{stOrange}
+\stsetrole{s}{stCoral}
+
+\stdim{T}{6}
+\stdim{dh}{3}
+
+\begin{document}
+\begin{tikzpicture}
+\ststage{SA}{每头打分：沿 $d_h$ 收缩}
+\strow{rowA}{T}
+  \ststack[role=q, bracket=true]{Q}{}{T}{dh}{3}
+  \stglyph{mA}{$\times$}
+  \ststack[role=k, bracket=true]{KT}{}{dh}{T}{3}
+  \stglyph{eA}{$=$}
+  \ststack[role=s]{S}{}{T}{T}{3}
+\strowend
+\stcaption{Q}{$\mathbf Q^{(i)}$}{$h\times T\times d_h$}
+\stcaption{KT}{$\mathbf K^{(i)\top}$}{$h\times d_h\times T$}
+\stcaption{S}{$\mathbf S^{(i)}$}{$h\times T\times T$}
+\sttopformula{F}{$S^{(i)}=Q^{(i)}K^{(i)\top}$}
+\stbbox{all}
+\stmeaningbox{mb}{120mm}{all}
+  {$T$ 时间；$d_h$ 头维；$h$ 头数画成 stack 深度}
+  {$Q/K$ 是 value；$S$ 是 score，不是 mask}
+  {沿 $d_h$ 收缩；$K^\top$ 换面，收缩边等长}
+\end{tikzpicture}
+\end{document}

examples/tensor-delegate/notes/notes.tex

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+\documentclass[a4paper]{article}
+\input{notes-macros}
+\renewcommand{\notetitle}{每头打分沿 $d_h$ 收缩}
+\renewcommand{\notepaper}{Head scores}
+\begin{document}
+\tableofcontents
+\newpage
+\input{sections/sec-01.tex}
+\input{sections/sec-02.tex}
+\input{sections/sec-03.tex}
+\appendix
+\section{符号表}
+\input{sections/symbols.tex}
+\end{document}

examples/tensor-delegate/notes/sections/sec-01.tex

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+\section{这篇论文在问什么}
+每头的 $Q$ 和 $K$ 沿哪一条边收缩，$K^\top$ 要不要真的换面？

examples/tensor-delegate/notes/sections/sec-02.tex

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+\section{主张与贡献}
+\splabel{C1}
+打分是 $(T\times d_h)(d_h\times T)\to(T\times T)$。$K^\top$ 必须物理换面，收缩边等长。
+
+先用中文说完，再写式子：
+
+\[
+S^{(i)}=Q^{(i)}K^{(i)\top}.
+\]
+
+\begin{itemize}
+\item $Q^{(i)}$ — 第 $i$ 头 query，$T\times d_h$
+\item $K^{(i)\top}$ — 转置后的 key，$d_h\times T$
+\item $S^{(i)}$ — 分数，不是 mask
+\end{itemize}
+
+\spfig{F2}{每头打分沿 $d_h$ 收缩。}{重绘自 fixture；toolkit: \texttt{supertensor}；ledger id: F2。}
+
+\subsection{本章小结}
+轴长是这张图的主张，所以走 supertensor，不走 superfig。

examples/tensor-delegate/notes/sections/sec-03.tex

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+\section{总结与延伸}
+形状对齐的公式图只交给 supertensor。